Will the Cubs actually play Pete Crow-Armstrong or will he ride the pine with Alexander Canario?

The Cubs are calling up their top prospect - but it's hard to be excited given the lack of playing time given to another top young talent since his promotion.
National League v American League
National League v American League / Matt Dirksen/GettyImages

It's been a long time since there was this much hype around a Cubs top prospect. But with outfielder Pete Crow-Armstrong set to join the team in Colorado ahead of a potential MLB debut, it's all eyes on the young outfielder, who will look to do what he can to help the team punch a postseason ticket for the first time since 2020.

Crow-Armstrong has answered every question thrown his way here in 2023, which he's spent between Double-A Tennessee and Triple-A Iowa. With the Smokies, the Gold Glove-caliber defender held his own at the plate, too, slashing .289/.371/.527 in 298 at-bats, swiping 27 bags for good measure.

Will the Cubs prioritize playing time for Pete Crow-Armstrong?

With the I-Cubs, he leveled off a bit, but still put up a respectable .271/.350/.479 line with 10 steals. He's shown some pop, with multiple grand slams of late, and one can only hope he can help jump start a Chicago offense that's sputtered of late. But that brings us to the question: how much will he actually play?

It's a fair query given the fact that fellow prospect outfielder Alexander Canario has all of one at-bat since joining the big league team back on Sept. 1. David Ross has made it clear he's planning on sinking or swimming with his veterans, which makes the promotion of Crow-Armstrong a bit of a head-scratcher.

How that all plays out will depend on what the corresponding move winds up being. But regardless, it's hard to envision any sort of scenario where he's getting regular plate appearances. He's the electric type of player who can change a game in multiple ways - and hopefully, he gets a fair shake at showing what he can do here as the Cubs look to lock down a postseason berth.